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6^(2x)=512/3
We move all terms to the left:
6^(2x)-(512/3)=0
We add all the numbers together, and all the variables
6^2x-(+512/3)=0
We get rid of parentheses
6^2x-512/3=0
We multiply all the terms by the denominator
6^2x*3-512=0
Wy multiply elements
18x^2-512=0
a = 18; b = 0; c = -512;
Δ = b2-4ac
Δ = 02-4·18·(-512)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36864}=192$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192}{2*18}=\frac{-192}{36} =-5+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192}{2*18}=\frac{192}{36} =5+1/3 $
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